Suppose you take on a loan for P Rupees, the tenure of the loan is n months (for example, n=240 for a 20-year loan), the monthly rate of interest is r (usually calculated by dividing the annual rate of interest quoted by the bank by 12, the number of months in a year, and dividing that by 100 as the rate is usually quoted as a percentage) and E Rupees is the EMI you have to pay every month. Let us use Pi to denote the amount you still owe to the bank at the end of the i-th month. At the very beginning of the tenure, i=0 and P0=P, the principal amount you took on as a loan.
At the end of the first month, you owe the bank the original amount P, the interest accrued at the end of the month r×P and you pay back E. In other words:
P1 = P + r×P - E
or to rewrite it slightly differently:
P1 = P×(1 + r) - E
Similarly, at the end of the second month the amount you still owe to the bank is:
P2 = P1×(1 + r) - E
or substituting the value of P1 we calculated earlier:
P2 = (P×(1 + r) - E)×(1 + r) - E
and once again expanding it and rewriting it slightly differently:
P2 = P×(1 + r)2 - E×((1 + r) + 1)
where "xy" denotes "x raised to the power y" or "x multiplied by itself y times". To make this look slightly simpler, we substitute "(1 + r)" by "t" and now it looks like this:
P2 = P×t2 - E×(1 + t)
Continuing in this fashion and calculating P3, P4, etc. we quickly see that Pi is given by:
Pi = P×ti - E×(1 + t + t2 + ... + ti-1)
At the end of n months (that is, at the end of the tenure of the loan), the total amount you owe to the bank should have become zero. In other words, Pn=0. This implies that:
Pn = P×tn - E×(1 + t + t2 + ... + tn-1) = 0
which means that:
P×tn = E×(1 + t + t2 + ... + tn-1)
We can simplify this further by noticing that we have a of n terms here with a common ratio of t and a scale factor of 1. The sum of such a series is given by "(tn - 1)/(t - 1)", which we substitute in the above equation to yield:
P×tn = E×(tn - 1)/(t - 1)
which can be rewritten as:
E = P×tn×(t - 1)/(tn - 1)
which can again be rewritten by substituting the value of t back as "(1 + r)" as:
E = P×r×(1 + r)n/((1 + r)n - 1)
and this is the formula for calculating your EMI.
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